A) \[pV\]
B) \[\frac{R}{y-1}\]
C) \[\frac{pV}{y-1}\]
D) \[\frac{y\,pV}{y-1}\]
Correct Answer: C
Solution :
The change in internal energy at constant pressure is \[dU=\frac{1}{\gamma -1}\,({{p}_{2}}{{V}_{2}}-{{p}_{1}}{{V}_{1}})\] Given, \[{{V}_{1}}=V\] \[{{V}_{2}}=2\,V\], \[{{p}_{1}}={{p}_{2}}=p\] \[\therefore \] \[dU=\frac{1}{\gamma -1}[\,p2V-pV]\] \[\Rightarrow \] \[dU=\frac{pV}{\gamma -1}\]
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