A) 0.053 nm
B) 0.106 nm
C) 0.2116 nm
D) 0.4256 nm
Correct Answer: C
Solution :
Key Idea Bohr5 radius is given by \[{{r}_{n}}=\frac{0.529\,\,{{n}^{2}}}{Z}\overset{o}{\mathop{A}}\,\] Bohrs orbit of hydrogen atom (n) = 2 Atomic number of hydrogen (Z) = 1 There of ore, \[{{r}_{n}}=\frac{0.529\times {{(2)}^{2}}}{1}\] \[=0.529\times 4\] \[{{r}_{n}}=2.116\,\overset{o}{\mathop{A}}\,\] = 0.2116 nm
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