A) 3.48 kJ
B) 3.74 kJ
C) 37.4 kJ
D) 34.8 kJ
Correct Answer: B
Solution :
Key Idea The kinetic energy (KE) of the ideal gas is given by \[KE=\frac{3}{2}nRT\] where, n = number of moles R = gas constant T = absolute temperature Here, n = 1 T = 300 K R = 8.314 J \[mo{{l}^{-1}}{{K}^{-1}}\] Now put these value in the above equation \[KE=\frac{3}{2}\times 1\times 8.31\times 300\] = 3741.3 J =3.74 kJ
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