A) passing \[C{{O}_{2}}\] into \[Ba{{O}_{2}}\]
B) adding \[Mn{{O}_{2}}\] to dil. \[{{H}_{2}}S{{O}_{4}}\]
C) adding \[N{{a}_{2}}{{O}_{2}}\] to cold water
D) adding \[Pb{{O}_{2}}\] into \[KMn{{O}_{4}}\]
Correct Answer: A
Solution :
Hydrogen peroxide is prepared in the laboratory by following methods- I. By the action of carbon dioxide on barium peroxide. \[Ba{{O}_{2}}+{{H}_{2}}O+C{{O}_{2}}\xrightarrow{{}}BaC{{O}_{3}}\downarrow +{{H}_{2}}{{O}_{2}}\] II. By the action of dil. \[{{H}_{2}}S{{O}_{4}}\] on hydrated barium peroxide. \[\underset{\begin{smallmatrix} hydrated \\ barium \\ peroxide \end{smallmatrix}}{\mathop{Ba{{O}_{2}}\,.\,\,8{{H}_{2}}O}}\,\,+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}BaS{{O}_{4}}+{{H}_{2}}S{{O}_{2}}\] \[+\,8{{H}_{2}}O\] III. By the action of phosphoric acid on barium peroxide. \[3Ba{{O}_{2}}+2{{H}_{3}}P{{O}_{4}}\to B{{a}_{3}}{{(P{{O}_{4}})}_{2}}\downarrow +3{{H}_{2}}{{O}_{2}}\] IV. By the action of dil. \[{{H}_{2}}S{{O}_{4}}\] on sodium peroxide. \[N{{a}_{2}}{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}}+{{H}_{2}}{{O}_{2}}\]
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