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AMU Medical AMU Solved Paper-2005

  • question_answer
    A gas has a vapour density 11.2. The volume occupied by 1 g of gas at NTP is

    A)  1L                                          

    B)  11.2 L

    C)  22.4 L                                   

    D)  unpredictable

    Correct Answer: A

    Solution :

                     Key Idea 1. Molecular weight                 = 2 \[\times \] vapour density Volume of 1 mole of gas at NTP = 22.4 L Vapour density of gas = 11.2 Hence, molecular weight \[=2\times 11.2\]                                                 = 22.4g \[\because \] The volume of 22.4 g gas at NTP                                                 = 22.4 L \[\therefore \] The volume of 1 g gas at NTP                                                 \[=\frac{22.4}{22.4}\times 1=1\,L\]


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