A) KI
B) NaCI
C) \[C{{l}_{2}}\]
D) \[{{I}_{2}}\] solution
Correct Answer: C
Solution :
Key Idea A more electronegative halogen displaces less electronegative halogen from its halides. The electronegativity order of halogen is as F > Cl > Br > I Chlorine is more electronegative than bromine so chlorine will liberate \[B{{r}_{2}}\] from KBr. \[C{{l}_{2}}+2KBr\xrightarrow{{}}2KCl+B{{r}_{2}}\] While iodine is less electronegative than bromine. So it cannot displace bromine from KBr. Note - A more electropositive halogen displaces less electropositive halogen from its halite. \[{{l}_{2}}+2KCl{{O}_{3}}\xrightarrow{{}}2Kl{{O}_{3}}+C{{l}_{2}}\]
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