A) 3,3-dimethyl-l-butene
B) 2,2-dimethyl-3-butene
C) l,l,l-trimethyl-2-propene
D) 3,3,3-trimethyl-2-propene
Correct Answer: A
Solution :
\[\underset{4}{\mathop{C}}\,{{H}_{3}}\underset{3}{\mathop{-}}\,\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{C}}\,}}\,-\underset{2}{\mathop{C}}\,H=\underset{1}{\mathop{C}}\,{{H}_{2}}\] This compound contains double bond, so the end of the longest chain which is near the double bond will be given number 1. This compound also contain side chain but preference will be given to double bond. Therefore, the IUPAC name of the compound is 3, 3-dimethyl-l-butene.
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