A) 50m
B) 100m
C) 200m
D) 400m
Correct Answer: B
Solution :
From equation of motion v = u + at where v is final velocity, u the initial velocity, a the acceleration and t the time. Given, u = 0, V = 72 km/h \[=72\times \frac{5}{18}=20\,m/s\] t = 10s \[\therefore \] \[20=0+a\times 10\] \[\Rightarrow \] \[a=\frac{20}{10}=2\,m{{s}^{-2}}\] From second equation of motion \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[s=0+\frac{1}{2}\times 2\times {{(10)}^{2}}=100\,m\]
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