A) \[-{{1.86}^{o}}C\]
B) \[{{1.86}^{o}}C\]
C) \[{{3.92}^{o}}C\]
D) \[{{2.42}^{o}}C\]
Correct Answer: A
Solution :
Molality of cane sugar solution \[=\frac{342}{342}=1\,m\] We know that, \[\Delta {{T}_{f}}={{K}_{f\,}}.\,\,m\] \[=1.86\times 1={{1.86}^{o}}\] Hence, freezing point of solution \[=0.00-(1.86)=-{{186}^{o}}C\]You need to login to perform this action.
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