A) less than w
B) equal to w
C) equal to 2 w
D) infinitely large
Correct Answer: D
Solution :
For equilibrium of body mg = 2T \[\cos \theta \] \[\therefore \] \[T=\frac{mg}{2\cos \theta }\] For the string to be horizontal, \[\theta \to {{90}^{o}}\] \[\therefore \] \[T-\frac{mg}{2\cos {{90}^{o}}}\Rightarrow T\to \infty \]You need to login to perform this action.
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