A) 200 J/s
B) 40 J/s
C) 140 J/s
D) 170 J/s
Correct Answer: C
Solution :
\[\vec{v}=(5\hat{i}-3\hat{j}+6\hat{k})\,m/s\] \[\vec{F}=(10\hat{i}+10\hat{j}+20\hat{k})\,N\] \[\therefore \] Power \[\vec{P}=\vec{F}.\,\vec{v}\] \[=(10\,\hat{i}+10\hat{j}+20\hat{k})\,.\,(5\hat{i}-3\hat{j}+6\hat{k})\] - 50 - 30 + 120 = 250 J/sYou need to login to perform this action.
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