A) 2 L
B) 4 L
C) L / 2
D) L / 4
Correct Answer: D
Solution :
\[L=mvr=m{{r}^{2}}\omega \] ... (i) Also, kinetic energy \[KE=\frac{1}{2}m{{v}^{2}}\] or \[KE=\frac{1}{2}m\,{{(r\omega )}^{2}}=\frac{1}{2}m{{r}^{2}}{{\omega }^{2}}\] \[\Rightarrow \] \[L=\frac{2KE}{\omega }\] Here, \[\omega =2\omega \] \[KE=\frac{1}{2}KE\] \[\therefore \] \[L=\frac{2KE}{\omega }=\frac{2\left( \frac{1}{2}KE \right)}{2\omega }=\frac{L}{4}\]You need to login to perform this action.
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