A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) 3
D) 2
Correct Answer: A
Solution :
Specific heat of water = 4200 J/kg - K Specific latent heat of fusion \[=3.36\times {{10}^{5}}J/kg\] Specific latent heat of vaporisation \[=22.68\times {{10}^{5}}J/kg\] Now, \[X\times {{10}^{-3}}\times 22.68\times {{10}^{5}}\] \[=Y\times {{10}^{-3}}\times 3.36\times {{10}^{5}}+Y\times {{10}^{-3}}\] \[\times 4200\times 100\]You need to login to perform this action.
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