A) \[\text{3}.\text{75 }\mu \text{F}\]
B) \[\text{5}.\text{25 }\mu \text{F}\]
C) \[\text{6}.\text{5 }\mu \text{F}\]
D) \[\text{1}0.\text{5 }\mu \text{F}\]
Correct Answer: A
Solution :
The circuit can be simplified as shown. It is a balanced Wheatstone bridge. \[\Rightarrow \] \[{{C}_{AB}}=\frac{5\times 3}{5+3}+\frac{5\times 3}{5+3}\] \[\Rightarrow \] \[{{C}_{AB}}=2\times \frac{15}{8}\] \[=\frac{30}{8}=3.75\,\mu F\]You need to login to perform this action.
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