A) 11 m/s
B) 10 m/s
C) 8 m/s
D) 3 m/s
Correct Answer: C
Solution :
Velocity of the ball after time t \[=\sqrt{v_{x}^{2}+v_{y}^{2}}\] \[=\sqrt{{{(4)}^{2}}+{{(gt)}^{2}}}\] \[=\sqrt{16+{{(10\times 0.7)}^{2}}}\] = 8 m/sYou need to login to perform this action.
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