A) \[8.314\times 273\times (-2)\]
B) \[8.314\times 300\times (-2)\]
C) \[8.314\times 27\times (-2)\]
D) \[8.314\times 300\times (-2)\]
Correct Answer: D
Solution :
\[2N{{H}_{3}}{{N}_{2}}+3{{H}_{2}}\] \[\because \] \[\Delta H=\Delta E+\Delta {{n}_{g}}RT\] \[\therefore \] \[\Delta H-\Delta E=\Delta {{n}_{g}}RT\] \[\Delta {{n}_{g}}=\] gaseous product - gaseous reactant = 4 - 2 = + 2 At \[{{27}^{o}}C\], \[\Delta H-\Delta E=2RT=2\times 8.31\times 300\]
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