A) 2 a
B) 8 a
C) 12 i2
D) 16 a
Correct Answer: C
Solution :
Input power\[=VI=200\times 10\] = 2000 W Output power \[=\frac{40}{100}\times 200=800\,W\] Power loss in heating the armature = 2000 - 800 = 1200 W \[\therefore \] \[{{I}^{2}}R=1200\] or \[R=\frac{1200}{{{I}^{2}}}\] \[=\frac{1200}{10\times 10}\] or R = 12 \[\Omega \]You need to login to perform this action.
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