A) 4
B) 3
C) 2
D) 1
Correct Answer: C
Solution :
Intensity at the centre of bright fringe, \[{{I}_{0}}=I+I+2\sqrt{II}\cos \,\,{{0}^{o}}\] \[{{I}_{0}}=2I+2I\] \[{{I}_{0}}=4I\] Intensity at a point distant P/4 (with a phase difference \[=2\pi /4=\pi /2)\] is \[I=I+I=2\sqrt{II}\cos \frac{\pi }{2}\] \[I=2I+2\sqrt{II}\times 0\] \[I=2I\] \[\therefore \] \[\frac{{{I}_{0}}}{I}=\frac{4I}{2I}=2\]You need to login to perform this action.
You will be redirected in
3 sec