A) 54%
B) 46%
C) 23%
D) 72%
Correct Answer: B
Solution :
According to Hannay and Smith equation \[\therefore \] % ionic character\[=16\,({{x}_{A}}-{{x}_{B}})+3.5\,{{({{x}_{A}}-{{x}_{B}})}^{2}}\] where, \[{{x}_{A}}\] and \[{{x}_{B}}\] are the electronegativites of the atoms A and B respectively. \[\therefore \] % ionic character \[=16\,(2)+3.5{{(2)}^{2}}\] = 32 + 14 = 46%You need to login to perform this action.
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