A) 5 MeV
B) 7 MeV
C) 10 MeV
D) 14 MeV
Correct Answer: B
Solution :
He atom has 2p + 2n Hence, Am \[=(2\times 1.0078+2\times 1.0087)-4.0026\] = 0.0304 u \[\therefore \] energy released \[=0.0304\times 931.5\,MeV\] = 28.3 MeV Binding energy per nucleon \[=\frac{28.3}{4}=7\] MeV (approximately)You need to login to perform this action.
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