A) \[{{10}^{3}}J\]
B) \[{{10}^{4}}J\]
C) \[\text{2}\times \text{l}{{0}^{\text{3}}}\text{J}\]
D) \[\text{4}\times \text{l}{{0}^{\text{4}}}\text{J}\]
Correct Answer: B
Solution :
\[v=u+at\] \[\therefore \] \[20=0+a\times 10\] \[20=a\times 10\] \[a=2\,m/{{s}^{2}}\] Now, \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[s=0+\frac{1}{2}\times 2\times 10\times 10\] s = 10 m Hence, work done \[W=F\times s\] \[W=ma\times s\] \[\therefore \] \[W=50\times 2\times 100\] W = 10000 \[={{10}^{4}}J\]
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