A) 250 K
B) \[250{}^\circ C\]
C) 2500 K
D) \[25{}^\circ C\]
Correct Answer: A
Solution :
\[\frac{pV}{T}=\] constant; V = constant \[\therefore \] \[\frac{p}{T}=\] constant \[\therefore \] \[\frac{p}{T}=\frac{100.4\,p}{100}\times \frac{1}{(T+1)}\] \[\frac{1}{T}=\frac{100.4}{100}\times \frac{1}{(T+1)}\] \[\frac{1}{T}=\frac{100.4}{100T+100}\] T = 250 KYou need to login to perform this action.
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