AMU Medical AMU Solved Paper-2008

  • question_answer
    The electronic configuration of a dipositive ion \[{{M}^{2+}}\] is 2, 8, 14 and its mass number is 56. The number of neutrons present is

    A)  32                                         

    B)  42

    C)  30                                         

    D)  34

    Correct Answer: C

    Solution :

                     Number of electrons in \[{{M}^{2+}}=24\] \[\therefore \] number of electrons in M = 26                 ie, atomic number (Z) = 26 Mass number  =56 \[\therefore \] number of neutrons = A - Z = 56 - 26 = 30.


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