A) 2
B) 1
C) \[1\frac{1}{2}\]
D) 0
Correct Answer: C
Solution :
From slow step, rate \[=k\,[{{B}_{2}}]\,[A]\] From 1st equation \[=\frac{{{[A]}^{2}}}{[{{A}_{2}}]}\] or \[[A]=\sqrt{{{K}_{eq}}[{{A}_{2}}]}\] \[=K_{eq}^{1/2}A_{2}^{1/2}[{{B}_{2}}]\]. Hence, rate \[=k\,[{{B}_{2}}]\,K_{eq}^{1/2}{{[{{A}_{2}}]}^{1/2}}\] \[=k\,{{[{{A}_{2}}]}^{1/2}}[{{B}_{2}}]\]. Hence, order \[=1\frac{1}{2}\]
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