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AMU Medical AMU Solved Paper-2008

  • question_answer
    The mass of helium atom of mass number 4 is 4.0026 u, while that of the neutron and proton are 1.0087 and 1.0078 respectively on the same scale. Hence, the nuclear binding energy per nucleon in the helium atom is nearly

    A)  5 MeV        

    B)  7 MeV

    C)  10 MeV       

    D)  14 MeV

    Correct Answer: B

    Solution :

                     He atom has 2p + 2n                 Hence, Am \[=(2\times 1.0078+2\times 1.0087)-4.0026\]                 = 0.0304 u \[\therefore \] energy released \[=0.0304\times 931.5\,MeV\]                                                 = 28.3 MeV Binding energy per nucleon \[=\frac{28.3}{4}=7\] MeV (approximately)


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