A) acidic solution of \[{{H}_{2}}S{{O}_{4}}\]
B) alkaline solution
C) acidic solution of HCl
D) neutral solution
Correct Answer: A
Solution :
\[{{K}_{2}}(S{{O}_{4}}).\,A{{l}_{2}}{{(S{{O}_{4}})}_{3}}.\,24{{H}_{2}}O\] gives \[{{K}_{2}}S{{O}_{4}}+\,A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+24{{H}_{2}}O\]. \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\] undergoes hydrolysis to give \[{{H}_{2}}S{{O}_{4}}\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+6{{H}_{2}}O\xrightarrow{{}}2Al{{(OH)}_{3}}+3{{H}_{2}}S{{O}_{4}}\]due to which aqueous solution of potash alum is acidic.
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