A) \[T=T=500\,N\]
B) \[T=T=250\,N\]
C) \[T=200\,N,T=300N\]
D) \[T=300\,N,T=200N\]
Correct Answer: D
Solution :
For the first case acceleration \[a=\frac{F}{{{m}_{1}}+{{m}_{2}}}\] is same in both the cases as \[{{F}_{1}}={{F}_{2}}\] masses of the blocks are same \[a=20\,m{{s}^{-2}}\] Now for first case the force is applied on block A \[\therefore \] \[T=500-10\times 20=300\,N\] Similarly, for block 2 the force is applied on block B \[\therefore \] \[T=500-15\times 20=200\,N\]You need to login to perform this action.
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