A) 2.4 mm
B) 1.2 mm
C) 2.4 cm
D) 1.2 cm
Correct Answer: A
Solution :
Given, \[\lambda =600\,\,nm\] a = 1 mm D = 2 m Now, the distance between two dark band on each side of the central maximum is the width of the central maximum. \[x=\frac{2\lambda D}{a}\] \[=\frac{2\times 600\times {{10}^{-19}}\times 2}{1\times {{10}^{-3}}}\] \[=24\times {{10}^{-4}}=2.4\,mm\]You need to login to perform this action.
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