A) \[\text{3}.\text{14m}{{\text{s}}^{-1}}\]
B) \[2.0\text{m}{{\text{s}}^{-1}}\]
C) \[1.0\text{m}{{\text{s}}^{-1}}\]
D) zero
Correct Answer: B
Solution :
Average velocity \[=\frac{displacement}{time\text{ }taken}\] or \[{{\vec{v}}_{av}}=\frac{\Delta \,\vec{r}}{\Delta \,t}\] As, displacement is AB = 2m \[{{\vec{v}}_{av}}=\frac{2\,m}{1\,s}=2\,s{{m}^{-1}}\]You need to login to perform this action.
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