A) \[\frac{Q}{4\pi {{\varepsilon }_{0}}{{x}^{2}}}\]
B) \[\frac{Q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\]
C) zero
D) None of these
Correct Answer: A
Solution :
Applying Gausss law \[\oint{\vec{E}.\,\vec{d}s=\frac{1}{{{\varepsilon }_{0}}}{{Q}_{enclosed}}}\] \[E.\,4\pi {{x}^{2}}=\frac{Q}{{{\varepsilon }_{0}}}\] \[E=\frac{Q}{4\pi {{\varepsilon }_{0}}{{x}^{2}}}\]You need to login to perform this action.
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