A) 4.0 mA (clockwise)
B) 4.0 mA (anti-clockwise)
C) 8.0 mA (clockwise)
D) 8.0 mA (anti-clockwise)
Correct Answer: C
Solution :
The time rate of flow of charge through any cross-section is called current. \[l=\frac{q}{t}=qv\] Here, q = e \[\therefore \] \[l=ev=1.6\times {{10}^{-19}}\times 5\times {{10}^{16}}\] = 8 mA The direction of the current is opposite to the motion of electron ie clockwise.You need to login to perform this action.
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