A) 33.0 MeV
B) 28.4 MeV
C) 23.8 MeV
D) 4.6 MeV
Correct Answer: C
Solution :
In the reaction \[_{1}^{2}H+_{1}^{2}H\xrightarrow{{}}_{2}^{4}He+Q\] Energy of reactants is \[=4\times 1.15\] (for 2 deuterons) = 4.60 MeV Energy of product \[=4\times 7.1=28.4\,\,MeV\] \[\therefore \] Q of reaction = 28.4 - 4.6 = 23.8 MeVYou need to login to perform this action.
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