A) \[{{k}_{1}}=k{{}_{1}}={{k}_{1}}\]
B) \[{{k}_{1}}=2k_{1}^{}=k_{1}^{}\]
C) \[4{{k}_{1}}=k_{1}^{}=2k_{1}^{}\]
D) \[4{{k}_{1}}=2k_{1}^{}=k_{1}^{}\]
Correct Answer: A
Solution :
Given, \[\frac{-d\,[{{N}_{2}}{{O}_{5}}]}{dt}=\frac{1}{2}\frac{d[N{{O}_{2}}]}{dt}=\frac{2d\,[{{O}_{2}}]}{dt}={{k}_{1}}[{{N}_{2}}{{O}_{5}}]\] \[\therefore \,\,{{k}_{1}}[{{N}_{2}}{{O}_{5}}]=2{{k}_{1}}[{{N}_{2}}{{O}_{5}}]=\frac{1}{2}{{k}_{1}}[{{N}_{2}}{{O}_{5}}]\] or \[{{k}_{1}}[{{N}_{2}}{{O}_{5}}]=k_{1}^{}[{{N}_{2}}{{O}_{5}}]=k_{1}^{}[{{N}_{2}}{{O}_{5}}]\] \[{{k}_{1}}=k_{1}^{}=k_{1}^{}\]You need to login to perform this action.
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