AMU Medical AMU Solved Paper-2010

  • question_answer
    A string is wound round the rim of a mounted flywheel of mass 20 kg and radius 20 cm. A steady pull of 25 N is applied on the cord. Neglecting friction and mass of the string, the angular acceleration of the wheel is

    A) \[\text{5}0{{\text{s}}^{-\text{2}}}\]                                       

    B)  \[\text{25}{{\text{s}}^{-\text{2}}}\]

    C) \[\text{12}.\text{5}{{\text{s}}^{-\text{2}}}\]                                      

    D)  \[\text{6}.\text{25}{{\text{s}}^{-\text{2}}}\]

    Correct Answer: C

    Solution :

                     The mass of flywheel = 20 kg Radius = 20 cm                                 \[=\frac{20}{100}m\]                                 \[=\frac{1}{5}m\] The moment of inertia \[=\frac{1}{2}M{{R}^{2}}\]                                 \[=\frac{1}{2}\times 20\times {{\left[ \frac{1}{5} \right]}^{2}}\]                                 \[I<0.4\,kg-{{m}^{2}}\] Angular acceleration \[\alpha =\frac{\tau }{I}\]                                 \[=\frac{FR}{I}\]                                 \[=\frac{25\times \frac{1}{5}}{0.4}\]                                 = 12.5 \[{{s}^{-2}}\]


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