A) 1, 2, 4
B) 3, 4, 5
C) 1,2,3,4
D) All of these
Correct Answer: C
Solution :
The equation of travelling wave \[y=\frac{1}{10}\sin (60\,t+2x)\] Compare with the standard wave equation \[y=a\sin \,(\omega \,t+kx)\] we get Amplitude, \[a=\frac{1}{10}m=10\,cm\] Angular frequency, \[\omega =60\] rad/s and Angular wave number, k = 2 rad/m \[\therefore \] Velocity of the wave \[v=\frac{\omega }{k}=\frac{60}{2}=30\]m/s \[\therefore \] Frequency of the wave \[f=\frac{\omega }{2\pi }=\frac{60}{2\pi }=\frac{30}{\pi }H\] Wavelength of the wave \[\lambda =\frac{2\pi }{k}=\frac{2\pi }{2}=\pi \,m\] There is positive sign between t and x terms, the given wave is moving in the negative x-direction.You need to login to perform this action.
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