A) seven times more than the deer
B) five times less than the deer
C) three times more than the deer
D) eleven times more than the deer
Correct Answer: A
Solution :
Heat \[\propto \] Area For deer, \[{{H}_{1}}\propto \frac{19,000}{1,50,000}\] For squirrel, \[{{H}_{2}}\propto \frac{530}{625}\] \[\frac{{{H}_{1}}}{{{H}_{2}}}=\frac{19,000/1,50,000}{530/625}\] \[\frac{{{H}_{1}}}{{{H}_{2}}}=\frac{0.26}{0.848}\] \[{{H}_{2}}=\frac{0.848}{0.126}{{H}_{1}}\] \[{{H}_{2}}=6.730\,{{H}_{1}}\] \[{{H}_{2}}=7{{H}_{1}}\] (approximately) So, the heat loss per cm3 volume of the squirrel will be approximately seven times more than the deer.
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