A) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] in acidic medium
B) \[Cr{{O}_{2}}C{{l}_{2}}/{{H}_{3}}{{O}^{+}}\]
C) PCC
D) \[{{C}_{3}}/{{H}_{2}}O\] -Zn dust
Correct Answer: D
Solution :
\[\underset{but-2ene}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,={{O}_{3}}\xrightarrow{{}}\] \[\xrightarrow{{{H}_{2}}O-Zn\,\,dust}\underset{ethanal}{\mathop{2C{{H}_{3}}CHO}}\,\]You need to login to perform this action.
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