2. Solved Papers
  3. AMU Medical

AMU Medical AMU Solved Paper-2010

  • question_answer
    A color coded carbon resistor has the colors orange, blue, green and silver. Its resistance value and tolerance percentage respectively are

    A)  \[\text{36}\times \text{l}{{\text{0}}^{5}}\Omega \text{ and 1}0%\]

    B)  \[\text{36}\times \text{l}{{\text{0}}^{4}}\Omega \text{ and 5}%\]

    C)  \[63\times {{10}^{5}}\Omega \,and\,10%\]

    D)  \[\text{35}\times \text{l}{{0}^{\text{6}}}\,\Omega \,\text{and}\,\text{5}%\]

    Correct Answer: A

    Solution :

                   
    Number Multiple Tolerance %
    Black          0 \[{{10}^{o}}\]
    Brown       1    \[{{10}^{1}}\]
    Red            2    \[{{10}^{2}}\]
    Orange      3     \[{{10}^{3}}\]
    Yellow       4    \[{{10}^{4}}\]
    Green        5      \[{{10}^{5}}\]
    Blue           6      \[{{10}^{6}}\]
    Violet         7       \[{{10}^{7}}\]
    Grey           8     \[{{10}^{8}}\]
    White        9      \[{{10}^{9}}\]
    Gold \[{{10}^{-1}}\] 5
    Silver \[{{10}^{-2}}\]  10
    No colour    20
    First colour gives first digit, second colour gives second digit and third digit gives the multiplier and fourth colour gives the tolerance. Resistance of the given resistor                 \[=36\times {{10}^{5}}\Omega \pm 10%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner