2. Solved Papers
  3. AMU Medical

AMU Medical AMU Solved Paper-2010

  • question_answer
    In an experiment with potentiometer, a cell of emf 1.25 V gives a balance point at 35 cm length of the wire. If the cell is replaced by another cell, the balance point shift to 63 cm. The emf of the second cell is

    A)  3.25 V                                  

    B)  2.5 V

    C)  2.25 V                                  

    D)  2 V

    Correct Answer: C

    Solution :

                     Given \[{{l}_{1}}=35\,cm,\,\,{{l}_{2}}=63\,cm\]                 \[{{E}_{1}}=1.25\,V;{{E}_{2}}=?\] \[\therefore \]  \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\]                 \[{{E}_{2}}=\frac{{{l}_{2}}}{{{l}_{1}}}\times {{E}_{1}}\]                 \[=\frac{63}{35}\times 1.25\]                 = 2.25 V


You need to login to perform this action.
You will be redirected in 3 sec spinner