AMU Medical AMU Solved Paper-2010

  • question_answer
    The magnitude of the magnetic field required to accelerate protons  (mass \[=\text{1}.\text{67x 1}{{0}^{-\text{27}}}\text{ kg})\]in a cyclotron that is operated at an oscillator frequency 12 MH is approximately

    A)  0.8 T                                     

    B)  1.6 T

    C)  2.0 T                                     

    D)  3.2 T

    Correct Answer: A

    Solution :

                     The cyclotron frequency, \[v=\frac{qB}{2\pi m}\] Magnetic field                   \[B=\frac{2\pi mv}{q}\] \[B=\frac{2\times 3.14\times 1.67\times {{10}^{-27}}\times 12\times {{10}^{6}}}{1.6\times {{10}^{-19}}}\] \[=78.6\times {{10}^{-2}}T\] B = 0.8 T                  (approximately)


You need to login to perform this action.
You will be redirected in 3 sec spinner