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AMU Medical AMU Solved Paper-2010

  • question_answer
    A light bulb is rated 100 W for a 220 V supply. The resistance of the bulb and the peak voltage of the source respectively are

    A)  2420 and 311 V                

    B)  4840 and 311 V

    C)  484 Q and 440 V              

    D)  242 Q and 440 V

    Correct Answer: B

    Solution :

                     The resistance of bulb                                 \[R=\frac{{{V}^{2}}}{P}\]                                 \[=\frac{220\times 220}{100}\]                                 \[=484\,\Omega \] The peak voltage of the source                 \[{{V}_{0}}=220\sqrt{2}=311\,V\]


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