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AMU Medical AMU Solved Paper-2010

  • question_answer
    The logarithm of the equilibrium constant of the cell reaction corresponding to the cell\[X(s)|{{X}^{2+}}(aq)||{{Y}^{+}}(aq)|\,Y(s)\] with standard cell potential, \[E_{cell}^{o}=1.2\,V\] is given by

    A)  12.5                                      

    B)  21.5

    C)  40.5                                      

    D)  47.2

    Correct Answer: C

    Solution :

                                    \[X(S)\xrightarrow{{}}{{X}^{2+}}+2{{e}^{-}}\] \[\frac{\begin{align}   & [{{Y}^{+}}{{e}^{-}}\xrightarrow{{}}Y]\times 2 \\  & 2{{Y}^{+}}+2{{e}^{-}}\xrightarrow{{}}2Y \\ \end{align}}{\frac{X(s)+2{{Y}^{+}}\xrightarrow{{}}{{X}^{2+}}+2Y}{{}}}\] Thus, n = 2                 \[{{E}^{o}}_{cell}=\frac{0.0591}{n}\log \,{{K}_{c}}\]                 \[1.2=\frac{0.0591}{2}\log \,{{K}_{c}}\]                 \[\log \,{{K}_{c}}=\frac{1.2\times 2}{0.0591}\]


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