question_answer

If the half cell reactions are given as (i) \[F{{e}^{2+}}(aq)+2{{e}^{-}}\to Fe(s);\,\,\,\,{{E}^{o}}=-0.44\,\,V\] (ii) \[2{{H}^{+}}(aq)+\frac{1}{2}{{O}_{2}}(g)+2{{e}^{-}}\to {{H}_{2}}O(l)\] \[{{E}^{o}}=+1.23\,\,V\] The \[{{E}^{o}}\] for the reaction \[Fe(s)+2{{H}^{+}}+\frac{1}{2}{{O}_{2}}(g)\to F{{e}^{2+}}(aq)+{{H}_{2}}O(l)\] is

A)  + 1.67V                               

B)  -1.67V

C)  + 0.79V                               

D)  -0.79V