A) M
B) M/2
C) M/4
D) M/5
Correct Answer: B
Solution :
\[{{\overset{-1}{\mathop{NH}}\,}_{2}}OH\xrightarrow{{}}{{\overset{+1}{\mathop{N}}\,}_{2}}O\] Conversion factor, \[n=+1-(-1)\] = + 2 Equivalent wt. of \[N{{H}_{2}}OH=\frac{molecular\,\,weight}{Conversion\text{ }factor}\] \[=\frac{M}{2}\]You need to login to perform this action.
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