A) 236.7 \[kJ\,k{{g}^{-1}}\]
B) 333.4 \[kJ\,k{{g}^{-1}}\]
C) -333.4 \[kJ\,k{{g}^{-1}}\]
D) -236.7 \[kJ\,k{{g}^{-1}}\]
Correct Answer: C
Solution :
\[\because \] \[{{H}_{2}}O(l)\xrightarrow{{}}{{H}_{2}}O(s)\,\,;\Delta H=-6.0\,kJ\,\,mo{{l}^{-1}}\] Number of moles in 1 kg water \[=\frac{1.00\times {{10}^{3}}}{18}=55.5\,mol\] When 1 mole of water freezes, energy change \[=6.0\,\,kJ\] \[\therefore \] When 55.5 mole water freezes, energy change \[=\frac{-6.0}{1}\times 55.56\,\,kJ\] \[=-333.36\,\,kJ\,k{{g}^{-1}}\] \[=-333.4\,\,kJ\,k{{g}^{-1}}\]
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