A) \[Cl{{O}^{-}}<ClO_{2}^{-}<ClO_{3}^{-}<ClO_{4}^{-}\]
B) \[ClO_{4}^{-}<ClO_{3}^{-}<ClO_{2}^{-}<Cl{{O}^{-}}\]
C) \[ClO_{4}^{-}<ClO_{3}^{-}<Cl{{O}^{-}}<ClO_{2}^{-}\]
D) \[ClO_{3}^{-}<ClO_{4}^{-}<ClO_{2}^{-}<Cl{{O}^{-}}\]
Correct Answer: A
Solution :
Hydration energy varies inversely with size. Among the given oxyacids, \[ClO_{4}^{-}\] has the smallest size because of the presence of \[C{{l}^{7+}}\]followed by \[ClO_{3}^{-}\] (with \[C{{l}^{5+}}\]), \[ClO_{2}^{-}\] (with\[C{{l}^{3+}}\]). \[Cl{{O}^{-}}\] has the largest size with \[C{{l}^{+}}\]ion. Hence, the order of increasing hydration energy is \[Cl{{O}^{-}}<ClO_{2}^{-}<ClO_{3}^{-}<ClO_{4}^{-}\]
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