A) \[P{{Q}_{3}}\]
B) \[{{P}_{3}}Q\]
C) \[{{P}_{2}}{{Q}_{3}}\]
D) \[{{P}_{3}}{{Q}_{2}}\]
Correct Answer: C
Solution :
Let the number of atoms in cubic close packing be x. \[\therefore \] Number of tetrahedral voids = 2 x Since, Q forms cubic close packing, the number of Q atoms = x P occupy one third of tetrahedral voids, the number of p atoms \[=\frac{2}{3}x\] \[\frac{Number\text{ }of\text{ }P\,\,atoms}{Number\text{ }of\text{ }Q\text{ }atoms}=\frac{2.\,x}{3x}=\frac{2}{3}\] Therefore, the formula of the compound is \[{{P}_{2}}{{Q}_{3}}\].
You need to login to perform this action.
You will be redirected in
3 sec
