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AMU Medical AMU Solved Paper-2011

  • question_answer
    Consider a soap film on a rectangular frame of wire of area \[\text{4}\times \text{4 cm2}.\] If the area of the soap film is increased to \[\text{4}\times 5\text{ cm2,}\] the work done in the process will be

    A) \[12\times {{10}^{-6}}J\]                              

    B)  \[24\times {{10}^{-6}}J\]

    C) \[60\times {{10}^{-6}}J\]                              

    D)  \[96\times {{10}^{-6}}J\]

    Correct Answer: B

    Solution :

                     Work done, \[W=2T\times A\]                 \[W=6\times {{10}^{-2}}\times [4\times 5-4\times 4]\times {{10}^{-4}}\]                                 \[=6\times {{10}^{-6}}\times 4\]                                 \[=24\times {{10}^{-6}}J\]                 (Film has two free surfaces).


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