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AMU Medical AMU Solved Paper-2011

  • question_answer
    The relation between time and displacement for two particles is given by                 (i) \[{{y}_{1}}=0.03\sin \,2\pi t(60t+{{\phi }_{1}})m\]                 (ii) \[{{y}_{2}}=0.06\sin \,2\pi t(60t+{{\phi }_{2}})m\]                 The ratio of intensities \[{{I}_{1}}:{{I}_{2}}\]of the two waves generated by the vibrations of the two particles in a given medium will be

    A)  1 :1                                       

    B)  1 : 2

    C)  1 : 4                                      

    D)  2 : 1

    Correct Answer: C

    Solution :

                     Given, \[{{y}_{1}}=0.03\sin 2\pi (60t+{{\phi }_{1}})m\]                 and        \[{{y}_{2}}=0.06\sin 2\pi (30t+{{\phi }_{2}})m\]                 \[\therefore \]  \[{{a}_{1}}=0.03\] and \[{{a}_{2}}=0.06\]                 \[\therefore \]  \[\frac{{{l}_{1}}}{{{l}_{2}}}={{\left( \frac{{{a}_{1}}}{a} \right)}^{2}}\]                                 \[={{\left( \frac{0.03}{0.06} \right)}^{2}}\]                                 \[=\frac{9}{36}=\frac{1}{4}\]


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