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AMU Medical AMU Solved Paper-2011

  • question_answer
    An observer moves towards a stationary source of sound with a velocity one - tenth the velocity of sound. The apparent increase in frequency is

    A)  zero                                     

    B)  2.5%

    C)  5%                                        

    D)  10%

    Correct Answer: D

    Solution :

                                    \[\frac{n}{n}=\left[ \frac{v+{{v}_{o}}}{v} \right]\]                                 \[\frac{n}{n}=\left[ \frac{330+33}{330} \right]\]                                 \[n[1.1]\,\,n\]                 Apparent increase in frequency \[=1.1\,\,n-n\]                                 \[=0.1\times n\]                                 \[=\frac{0.1\times n\times 100}{n}=10%\]


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